ФОТОГРАФИЯ! Найдите область определения функции

Решите задачу:

$y=\frac{\sqrt{9-x^2}}{x+1}\\\\ \left \{ {{9-x^2 \geq 0} \atop {x+1\ne 0}} \right. \; \left \{ {{x^2-9 \leq 0} \atop {x\ne -1}} \right. \; \left \{ {{-3 \leq x \leq 3} \atop {x\ne -1}} \right. \\\\x\in [-3-1)U(-1,3]$