Xy+x=56 xy+y=54 решить систему уравнений

Решите задачу:

$[tex] xy+x=56 \\ xy+y=54 \\\\(xy+x)-(xy+y)=56-54 \\ x-y=2 \\ x=y+2 \\ (y+2)y+y-54=0 \\ y^2+2y+y-54=0 \\ y^2+3y-54=0 \\ D=9+54*4=225 \\ y_{1,2} = \frac{-3б15}{2} \\ y_1 = \frac{-3+15}{2} = 6 \\ y_2 = \frac{-3-15}{2} = - 9 \\ x_1 = 6+2 = 8 \\ x_2 = -9+2 = -7 \\ Answer \quad \{y=6; x=8\} ; \{y=-9; x=-7\} \\$