Решите неравенство 1/x-2/x-3 ≤ 0

1/x-2/x-3 ≤ 0
1/x-2/x-3≤0,x≠0
$\frac{1-2-3x}{x} \leq 0$
$\frac{-1-3x}{x} \leq 0$
$\left \{ {{-1-3x \leq 0 } \atop {x\ \textgreater \ 0}} \right.$
$\left \{ {{-1-3x \geq 0} \atop {x\ \textless \ 0}} \right.$
$\left \{ {{x \geq - \frac{1}{3} } \atop {x\ \textgreater \ 0}} \right.$
$\left \{ {{x \leq - \frac{1}{3} } \atop {x\ \textless \ 0}} \right.$
x∈(0,+∞)
x∈(-∞,-1/3)
x∈(-∞,-1/3)∪(0,+∞),x≠0
x∈(-∞,-1/3)∪(0,+∞)