Объесните, как решать эту систему уравнений:

$\left \{ {{ \frac{x-1}{4}- \frac{y+1}{3}=4|*12 } \atop { \frac{x+3}{2} - \frac{y-2}{3} =2|*6}} \right. \; \; =\ \textgreater \ \; \; \left \{ {{3(x-1)-4(y+1)}=48 \atop {3(x+3)-2(y-2)=12}}\; \; =\ \textgreater \ \right.\\\\=\ \textgreater \ \left \{ {{3x-3-4y-4=48} \atop {3x+9-2y+4=12}} \right.\; \; =\ \textgreater \ \left \{ {{3x-4y=60} \atop {3x-2y}=-1|*(-1)} \right. \; \; =\ \textgreater \ \\\\=\ \textgreater \ \left \{ {{3x-4y=60} \atop {-3x+2y=1}}+ \right. \; \; =\ \textgreater \ -2y=61=\ \textgreater \ y=-30,5\\\\3x-4(-30,5)=60\\3x+122=60\\3x=-62\\x=-20 \frac{2}{3} \\y=-30,5=-30 \frac{1}{2}$

Ответ: $(-20 \frac{2}{3} ;-30 \frac{1}{2})$